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2 years ago

I need help asap please

Mathematics

1 answer:

Step2247 [10]2 years ago

8 0

Answer:

Angle A: 30°

Angle B: 60°

Angle C: 90°

Step-by-step explanation:

Hopefully this helps! :)

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Ms. Wittenberg had a total of $220. She spent $11 at Dunkin' Donuts.

Sphinxa [80]

She spent 5% of her money

8 0

2 years ago

Analyze this student's work. What did the student do correctly? What did he do incorrectly?

saw5 [17]

I don’t think he did distributive property

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2 years ago

Kenya is solving the equation 5 3/4 - 1/6x = 4 1/2. She gets to 1 1/4 = 1/6x. Is this a valid way to solve the equation? answer

Alona [7]

Answer:

15/2

Step-by-step explanation:

5 3/4 - 1/6x = 4 1/2

move the variable to it's own side.

5 3/4 - 4 1/2 = 1/6x

change the subtracting side to have common denominators

5 3/4 - 4 2/4 = 1/6x

1 1/4 = 1/6 x

divide both sides by 1/6, same thing as multiplying both sides by 6 (reciprocal)

30/4 = x

reduce: 15/2 = x

8 0

3 years ago

The answer to this word problem usinf discriminant

solniwko [45]

$\bf h=-9.8t^2+45t+1.2\implies 64.5=-9.8t^2+45t+1.2
\\\\\\
0=-9.8t^2+45t-63.3\\\\
-------------------------------$

$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic}
\\\\\\
0=\stackrel{\stackrel{a}{\downarrow }}{-9.8}t^2\stackrel{\stackrel{b}{\downarrow }}{+45}t\stackrel{\stackrel{c}{\downarrow }}{-63.3}
~~~~~~
\stackrel{discriminant}{b^2-4ac}=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}
\\\\\\
(45)^2-4(-9.8)(-63.3)\implies -456.36$

the discriminant is a negative value, thus no solution for such quadratic, meaning if we use h=64.5 like we did, there's no "t" seconds at which point the ball hits the batting cage.

8 0

2 years ago

Amanda created a table to help her represent the sample space of spinning a spinner and flipping a coin.

OlgaM077 [116]

Answer:

$\sf \dfrac{1}{8}$

Step-by-step explanation:

Spinner choices: Red, Green, Yellow, Blue

Coin choices: Heads, Tails

$\large\begin{array}{| c | c | c | c | c |}\cline{1-5} & \sf Red & \sf Green & \sf Yellow & \sf Blue\\\cline{1-5} \sf Heads & RH & GH &YH & BH \\\cline{1-5} \sf Tails &RT & GT& YT& BT\\\cline{1-5}\end{array}$

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

$\implies \sf P(blue)=\dfrac{1}{4}$

$\implies \sf P(heads)=\dfrac{1}{2}$

$\implies \sf P(blue)\:and\:P(heads)=\dfrac{1}{4} \times \dfrac{1}{2}=\dfrac{1}{8}$

5 0

1 year ago