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nordsb [41]
3 years ago
6

HELP! I NEED THIS ANSWER, WILL GIVE BRAINLIEST

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

BBBBBBBBBBBBBBBBBBBBBBBBBBBB

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Y= (x-9) (x+3)
juin [17]

Answer:

y = x² − 6x − 27

Step-by-step explanation:

To distribute, you can use something called FOIL.  It stands for First, Outer, Inner, Last.

First, multiply the First term in each factor.

x · x = x²

Now multiply the Outer terms in each factor.

x · 3 = 3x

Next multiply the Inner terms in each factor.

-9 · x = -9x

Finally, multiply the Last terms in each factor.

-9 · 3 = -27

Add them all up:

x² + 3x − 9x − 27

x² − 6x − 27

4 0
3 years ago
Rectangle PQRS with vertices P(- 6, 9) , Q(3, 6); R(0, - 9) and S(- 9, - 6)
STatiana [176]

Answer:

multiply the original coordinate by 3 so its c

Step-by-step explanation:

multiply the original coordinate by 3

6 0
2 years ago
Jeff wants to buy tickets for a football game for his friends. The stadium is selling tickets for $7 each. The stadium requires
aniked [119]

Your answer is D){28, 42, 56, 70, 84}

To answer this question you just have to make sure the amount he pays is a multiple of 7.If you know you times table then this should be easy

Times table of 7:

7,14,21,28,35,42,49,55,63,70,77,84.

Now you just need to find an answer choice who has these numbers.Lets check it out!

A) 11 isn't a multiple of 7

B) 56 isn't a multiple of 7

C) None of these are multiples of 7 except 7 so this is also incorrect

D) This is correct because they are all multiples of 7

Hope this makes sense.

7 0
2 years ago
Johan can get lunch at Joe’s Deli for $12, and he can get lunch at Majestic for $8. In one month, Johan spent $96 on lunches (an
Triss [41]

Answer: D

Step-by-step explanation:

It’s really obvious just circle D

4 0
2 years ago
What is the simplified form of this expression 7(^3sqrt2x)-3(^3sqrt16x)-3(^3sqrt8x)
trasher [3.6K]

Answer:

<h2>7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x</h2>

Solution,

7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\  = 7 \sqrt[3]{2x}  - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x}  - 3 \times  \sqrt[3]{2 \times 2 \times 2x}  \\  = 7 \sqrt[3]{2x}  - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 3 \times 2 \times  \sqrt[3]{2x}  - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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