Whats four divided by one third??

In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 25

Anastaziya [24]

Answer:

16 faults

Step-by-step explanation:

The correct question is

In tennis, a first serve can be an ace, a fault, or it can be returned. In one match, a tennis player hit 24 aces, which was 2/5 of all her first serves. If 1/3 of her first serves were returned, how many of the tennis player's first serves were faults?

Let

x -----> the number of all her first servers

y ----> the number of first services returned

z ---> the number of first services faults

we know that

The number of aces plus the number of returned plus the number of faults must be equal to the number of all her first services

so

$x=24+y+z$

step 1

Find out the number of all her first servers

we have that

$24=\frac{2}{5}x$

Solve for x

$x=24(5)/2\\x=60\ first\ services$

step 2

Find out the number of first services returned

$y=\frac{1}{3}x$

substitute the value of x

$y=\frac{1}{3}(60)=20\ returned$

step 3

Find out the number of first services faults

$x=24+y+z$

we have

$x=60\\y=20$

substitute and solve for z

$60=24+20+z$

$60=44+z$

$z=16\ faults$

6 0

3 years ago

Ian invests $250 each month for 9 months into an account that pays 6% APR compounded monthly. What is the future value of Ian's

Feliz [49]

Answer:

B

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The difference of 5 times a number and 8 is 27. which equation below can be used to find the unknown number?

Nady [450]

5n - 8 = 27 is ur answer

5 0

4 years ago

Read 2 more answers

Solve by elimination: 7x-9y=29 7x+2y=-15

Alexxandr [17]

Answer:

x = 125/7 , y = -11/3

Step-by-step explanation:

7x - 9y = 29

7x + 2y = - 15

- - + (subtracting)

__________

0 - 12y = 44

y = 44/-12

y = - 11/3

Putting y in first equation,

7x - 9 (-11/3) = 29,we get

x = 125/7 or 17.8

Hope it helps!

7 0

4 years ago

Solve this simultaneous equation x/2+ y/3=13/6 2x/7-y/4=5/14

Yuri [45]

9514 1404 393

Answer:

(x, y) = (3, 2)

Step-by-step explanation:

These look like solution using elimination or substitution could be tedious, so we'll use the "cross multiplication" technique for solution. This requires each equation be in general form: ax+by+c = 0.

The first equation can be multiplied by 6 and 13 subtracted.

x/2 +y/3 = 13/6

3x +2y = 13

3x +2y -13 = 0

The second equation can be multiplied by 28 and 10 subtracted.

2x/7 -y/4 = 5/14

8x -7y = 10

8x -7y -10 = 0

Now, an array of coefficients can be constructed. The last column is the same as the first.

$\begin{array}{cccc}3&2&-13&3\\8&-7&-10&8\end{array}$

Cross-multiplying adjacent columns, we can write the equation ...

1/(3(-7)-8(2)) = x/(2(-10)-(-7)(-13)) = y/(-13(8)-(-10)(3))

1/-37 = x/-111 = y/-74

Solving for x and y, we have ...

x = -111/-37 = 3

y = -74/-37 = 2

The solution is (x, y) = (3, 2).

4 0

3 years ago