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mariarad [96]
3 years ago
11

Solve this simultaneous equation x/2+ y/3=13/6 2x/7-y/4=5/14

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

9514 1404 393

Answer:

  (x, y) = (3, 2)

Step-by-step explanation:

These look like solution using elimination or substitution could be tedious, so we'll use the "cross multiplication" technique for solution. This requires each equation be in general form: ax+by+c = 0.

The first equation can be multiplied by 6 and 13 subtracted.

  x/2 +y/3 = 13/6

  3x +2y = 13

  3x +2y -13 = 0

The second equation can be multiplied by 28 and 10 subtracted.

  2x/7 -y/4 = 5/14

  8x -7y = 10

  8x -7y -10 = 0

Now, an array of coefficients can be constructed. The last column is the same as the first.

  \begin{array}{cccc}3&2&-13&3\\8&-7&-10&8\end{array}

Cross-multiplying adjacent columns, we can write the equation ...

  1/(3(-7)-8(2)) = x/(2(-10)-(-7)(-13)) = y/(-13(8)-(-10)(3))

  1/-37 = x/-111 = y/-74

Solving for x and y, we have ...

  x = -111/-37 = 3

  y = -74/-37 = 2

The solution is (x, y) = (3, 2).

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Answer:

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Step-by-step explanation:

Given:

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Consider a Quadrilateral ABCD as trapezoid with diagonals as AC and BD

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Option D is correct.

Figures are missing in the question.

The images below shows the missing figures of question.

<h3>Solution:</h3>

For congruent figures, we need the same shape, same area, and inverse direction.

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In the case of geometric figures, line segments with the same length are congruent and angle with the same measure are congruent.

In elementary geometry the word congruent is often used as follows. The word equal is often used in place of congruent for these objects.

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