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xenn [34]
3 years ago
14

What adds to make -7 and times to make +10

Mathematics
2 answers:
pav-90 [236]3 years ago
8 0
17
it's 17+(-7)=10
i hope that answers your problem
AlekseyPX3 years ago
7 0
-5 + (- 2) = -7
-5 * (-2) = 10

Answer:
-5 and -2

Hope this helps!
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When darryl and his family moved to the city, there were 133 retail stores. use the equation to predict what year darryl’s famil
devlian [24]

According to the information, the year Darryl and his family arrived in the city was 2001.

<h3>How to calculate the year that Darryl and her family moved to the city?</h3>

To calculate what year Darryl and her family moved to this city, we need to replace the value of x with the year they moved and the result should be 133.

  • y = 11x + 12
  • 133 = 11x + 12
  • 133 - 12 = 11x
  • 121 = 11x
  • 121 ÷ 11 = x
  • 11 = x

According to the above, 11 years passed from 1990 to the year in which Darryl and his family moved to the city, that is, the year 2001.

Note: This question is incomplete because the options and image are missing. Here is the complete information:

Learn more about equation in: brainly.com/question/10413253

4 0
1 year ago
How many two-digit numbers are there in which the tens digit is greater than<br> the ones digit?
Dovator [93]

there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

#SPJ1

7 0
1 year ago
I neeeee helppppppppp
kaheart [24]

Answer:

The pin number is 1147

Step-by-step explanation:

We have given that:

Maritza remembers her PIN because it is the product of two consecutive prime numbers that is between 1000 and 1500.

Pin number is between 1000 and 1500

PIN is the product of two consecutive prime numbers.

Prime numbers are those numbers which are divisible by one or itself only.

So,

prime numbers are 1, 3, 5, 7,………29, 31,37, 41, …..

Multiply  29 x 31 = 899  which does not come in the range of 1000 and 1500.

Next,

31 x 37 = 1147 this is between 1000 and 1500

Next

37 x 41 = 1517, which is above 1500.

Thus the pin number is 1147....

7 0
3 years ago
Find the measure of angle 1.<br> (Please help! and explain!)
lys-0071 [83]

Answer:

40 degrees.

Step-by-step explanation:

Since the angle opposite 1 is 40 degrees, and is the same as 1, the angle is forty degrees.

8 0
3 years ago
Find the values of the sine, cosine, and tangent for ZA.<br><br> (TOP OF TRIANGLE IS (A))
Sloan [31]

\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\

  • AC = 7 m
  • BC = 4 m

⠀⠀⠀

\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\

\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

  • sin A = Perpendicular/Hypotenus = \sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}

⠀⠀⠀

  • cos A = Base/Hypotenus = \sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}

⠀⠀⠀

  • tan A = Perpendicular/Base = {\sf{\pink{\dfrac{4}{7}}}}

⠀⠀⠀

\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}

4 0
2 years ago
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