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4 years ago

The diameter of a circle is 6 inches. What is the circle's circumference?

Mathematics

1 answer:

katrin2010 [14]4 years ago

4 0

Answer:

brainiest? 37.68

Step-by-step explanation:

6 x 2 = 12

12 x 3.14 = 37.68

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MATH HELP PLZ!!!

RoseWind [281]

Answer:

a) $tan (157.5) = \frac{1-cos 315}{sin315}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos 330° = 1- 2 sin² (165°)

Step-by-step explanation:

Step(i):-

By using trigonometry formulas

cos2∝ = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ = 2 cos² ∝/2

$cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}$

cos2∝ = 1- 2 sin² ∝

cos∝ = 1- 2 sin² ∝/2

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

Step(i):-

Given

$tan\alpha = \frac{sin\alpha }{cos\alpha }$

we know that trigonometry formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

Given

$tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }$

put ∝ = 315

$tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }$

multiply with ' 2 sin (∝/2) both numerator and denominator

$tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2} }{2sin(\frac{315}{2} cos(\frac{315}{2}) }$

Apply formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

now we get

$tan (157.5) = \frac{1-cos 315}{sin315}$

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 330° above formula

$sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}$

$sin^{2} (165) = \frac{1-cos (330) }{2}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c )

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 315° above formula

$sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos∝ = 1- 2 sin² ∝/2

put ∝ = 330°

$cos 330 = 1 - 2sin^{2} (\frac{330}{2} )$

cos 330° = 1- 2 sin² (165°)

3 0

3 years ago

What is the estimate square root 65 to the nearest tenth

V125BC [204]

The square root of 65 is approximately 8.1

4 0

4 years ago

Read 2 more answers

Point G is on line segment FH. Given FH = 19 and FG = 12, determine the length GH.

Alex777 [14]

Answer:

Step-by-step explanation:

Let’s think about this like a number line.

If we have a number line with the ends of F and H, and G is somewhere in between, it would look something like this.

F———-G———H

We know that FH = 19 and that FG is 12.

This means that GH will be the FH - FG

$19 - 12 = 7$

So FG is 7.

Hope this helped!

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4 years ago

What is the factored form of 125a^6-64?

Afina-wow [57]

Answer:

It's B. on EtDtGtE

Step-by-step explanation:

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4 years ago

Find the next term in the sequence 3,7,10,17,27,44,___

Lyrx [107]

The top one might be 48 And bottom is 66?

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3 years ago

The diameter of a circle is 6 inches. What is the circle's circumference?​

The diameter of a circle is 6 inches. What is the circle's circumference?