Answer:
73.12 yd²
Step-by-step explanation:
Find the triangle first
A=½bh
a=½×12×8
a=6×8
a=48->triangle
semicircle=
a=½×pi×r²
a=½×3.14×4²
a=½×3.14×16
a=8×3.14
a=25.12
add these two
48+25.12=73.12 yd²
Answer:
Step-by-step explanation:
Comment
The first step is to find the surface area of 1 fence post.
The formula is
Area_ends = 2 pi r^2 for the ends.
Area_body = 2*pi*r * h
Givens
r = d/2 r is the radius ; d is the diameter
r = 1/2 foot
h = 10 feet
Solution
1 fence post
Area = ends + area body
Area = 2*3.14 * (1/2)^2 + 2 * pi * r * h
Area = 2*3.14* (1/2)^2 + 2 * 3.14 * 1/2 * 10
Area = 1.57 + 31.4
Area = 32,97 square feet.
10 fence posts
10*32.97 = 329.7 square feet
Answer
10 fence posts have 329.7 square feet in area.
Answer:
slope = 3
y-intercept = -4
y = 3x-4
Step-by-step explanation:
Minimum = 827
Q1 = 886
Median = 995.5
Q3 = 1095.5
Maximum = 1229
1500:75 A:50
So 1500-15 seconds is A
Not sure what else but there’s an equation
