5(x-5)^4(x+4)
you raise x-5 to the 4th power because 5 has a multiplicity of 4
If x=3 then the f(x)=4
If x=6 then the f(x)=7
If x=7 then the f(x)=8
The vector i=<1,0> and j=<0,1> so the i+j=<1+0,0+1>=<1,1>. The length of this vector is easy: |i+j|=<span>2–√</span>
to make the vector i+j=<1,1> a unit vector we rescale it by it's
length (i.e. divide i+j by its length) , v=(i+j)/(|i+j|)
thus we have v=<span>1/<span>2–√</span><1,1></span> or <span><1/<span>2–√</span>,1/<span>2–√</span>></span>
If you check the length of this vector v, you see it indeed does have
length =1. It is parallel to the vector i+j because it's components are
proportional to the components of i+j=<1,1>.
0.05x+0.12 (19660-x)=2060
Solve for x
X=4274.29 at 5%
19,660−4,274.29
=15,385.71 at 12%
