Help me please!! As soon as you can!!

HELP I NEED THIS NOW!!!!

borishaifa [10]

Answer:

So, The area of trapezoid = 4.413 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and m∠NMK = 65° , OT = R

So, m∠MNP = 180° - 65° = 115° ⇒ supplementary interior angles.

Join ON ⇒ ΔOSN is a right triangle at S.

And NP, NM are tangents to the circle

So, ON bisects the angle ∠MNP = ∠MNS

∠ONS = (∠MNS)/2 = 115/2 = 57.5°

So, tan (∠ONS) = OS/NS = R/(NS)

NS = R/tan (∠ONS)=R/(tan 57.5°) ≈ 0.637 R

∴ NP = 2 * NS = 1.274 R

Construct: a line parallel to ST from N to line MK

let the intersection point be Q ⇒ NQ = 2R

So, Δ NQM is a right triangle at Q

tan (∠NMQ) = tan 65 = NQ/MQ

MQ = NQ/(tan 65)=2R/tan 65 ≈ 0.932 R

∴ MK = 2 MT = 2 (MQ + QT) ⇒ QT = NS

= 2 (MQ + NS ) = 2( 0.932 R + 0.637 R) = 2 * 1.569 R

∴ MK = 3.139 R

Now, area of trapezoid = height × (sum of parallel sides/ 2)

Area = ST * (NP + MK)/2

= 2R * (1.274 R + 3.139 R) / 2

= 2R * 4.413 R /2

= 4.413 R²

So, The area of trapezoid = 4.413 R²

5 0

2 years ago

Need help 2x+10 2x find x

Yuri [45]

Answer:5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If anyone can help i would appreciate it. Ill give brainiest to anyone who answers with out a link

vovikov84 [41]

Answer:

im pretty sure what u have ther is right

5 0

3 years ago

Read 2 more answers

If a survey of a movie shows that 50% of all people who like the movie, enjoyed the official movie soundtrack too. If a total of

Murljashka [212]

Answer:

For the first question the sample size is n= 3850

$ME= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$\hat p \pm ME$

And replacing we got:

$0.5- 0.016 = 0.484$

$0.5+ 0.016 = 0.516$

We are confident at 95% that the true proportion of all people who like the movie is between 0.484 and 0.516.

Step-by-step explanation:

We have the following info given:

$\hat p = 0.5$ represent the estimated proportion of all people who like the movie

$n = 3850$ represent the sample size selected

For the first question the sample size is n= 3850

For the second part they gives to us the margin of error:

$ME = 0.016$

We know that the confidence interval for a population proportion $p$ of interest is given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

And the margin of error is given by:

$ME= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

So then the confidence interval can be found with this formula:

$\hat p \pm ME$

And replacing we got:

$0.5- 0.016 = 0.484$

$0.5+ 0.016 = 0.516$

We are confident at 95% that the true proportion of all people who like the movie is between 0.484 and 0.516.

5 0

3 years ago

Someone please helppp

RSB [31]

0.5 inches ph * 3 hours = 1.5 inches

+ 10 inches he started with.

= 11.5 inches.

I don’t know about the second question

5 0

3 years ago