All categories

3 years ago

Graham is graphing the inequality x greater-than 4. He draws a number line and shades over the numbers that are greater than 4.

Mathematics

1 answer:

schepotkina [342]3 years ago

8 0

Answer:

Draw an open circle at 4

Step-by-step explanation:

You might be interested in

Can someone help pls

WITCHER [35]

I think its A. translation, translation

6 0

3 years ago

A farmer was counting his chickens and pigs. He had 16 animals in all and counted 54 legs. How many chickens does he have

Vikentia [17]

Answer:

5 chickens

Step-by-step explanation:

Let's set chickens and pigs with variables "c" and "p" respectively.

We know there a 16 animals in all, so there are:

c+p=16

We know there are 54 legs and chickens have 2 legs and pigs have 4 legs each:

2c+4p=54

Now we have our system of equations:

c+p=16

2c+4p=54

We are trying to find the number of chickens, so we write the first equation in respect to c.

p=16-c

Substituting the first derived equation to equation two:

2c+64-4c=54

Simplifying:

64-2c=54

2c=10

c=5

So there are 5 chickens.

8 0

3 years ago

I'm spending lots of points so please help ahaha-

umka2103 [35]

(2x+24)
(11b-33)
(8s-8)
(36+6y)
(25z-100)
(35w-70)

5 0

3 years ago

Read 2 more answers

Solve for x. logo(x-2) + log(x + 3) = 2

amid [387]

Answer:

x=-1-5√17/2

Step-by-step explanation:

logo((x-2)(x+2))=2

logo(x²+3x-2x-6)=2

x²+3x-2x-6=10²

x²+x-6=100

x²+x-106=0

x=-1+5√17/2

5 0

2 years ago

A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation

Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an $m\times n$ matrix. Let $T :U\to V$ be the corresponding linear transformationover the field F and $\theta$ be identity vector in V. Now if $x\in Ker( T)\implies T(x)=\theta$ .

(1) The kernel of a linear transformation is a vector space : True.

Let $x,y\in Ker( T)$ , then,

$T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)$

hence the kernel is closed under addition.

Let $\lambda\in F, x\in Ker( T)$ , then

$T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta$

$\lambda x\in Ker(T)$ and thus Ket(T) is closed under multiplication

Finally, fore all vectors $u\in U$ ,

$T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta$

$\implies \theta\in Ker(T)$

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is $\mathbb R^m$ : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in $\mathbb R^m$

: False

The null space that is dimension of solution space of an m x n matrix is always in $\mathbb R^n$ .

(4) The column space of A is the range of the mapping $x\to Ax$

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0

3 years ago