Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
√z = 13 - 8
√z = 5
z = 5²
z = 25
In this case the z can be any number, however z cannot be less than 0 and that is the restriction. (for example; √-1 = irrational number, cannot be solved.)
Answer:
(2,4)
Step-by-step explanation:
the point where the lines intercept is the solution, so it is (2,4)
Answer:
20+4x
Step-by-step explanation:
Distributive property is quite easy to learn... its just multiplication in an easier form to visualize once you're used to using it.
To first start this problem you want to use the number 4 in the expression 4(5+x). You then want to multiply 4 by both terms inside of the parentheses. So you would do both 4*5 and 4*x. You would then get 20+4x because 4*5=20 and 4*x is just put together as 4x.
Answer:
$1.60
Step-by-step explanation:
Please see the attached pictures for full solution.
