The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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Answer:
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Answer:
Explanation:
Solving (a): P(Joe)
To get this probability, we simply add up the items in the column named Joe.
These items are:
Joe: 34 and 70
And the total is:
The overall population of the system is:
So:
Solving (a): P(Joe and North Side)
To get this probability, we simply get the intersecting element of Joe column and North Side row.
From the table, the intersecting element is:
Joe and North Side: 70
The overall population of the system is:
