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Radda [10]
2 years ago
12

Andre hit a golf ball from the ground and its movement follows the equation hbracket(t)=-16sup(t,2)+44t, where t is the time in

seconds, and hbracket(t) is the height of the ball at a given time t. Find the time that it took the golf ball to hit the ground again correct to two decimal places.
Mathematics
1 answer:
Natasha2012 [34]2 years ago
4 0

Answer: the golf ball with hit the ground again after 2.75 seconds

Step-by-step explanation:

The movement of the golf ball from the ground follows the equation h(t)=-16t^2+44t,

where t is the time in seconds, and h(t) is the height of the ball at a given time t

By the time the golf ball hit the ground, the height from the ground would be zero. This means that we would equate the quadratic equation to zero. It becomes

-16t^2+44t = 0

Dividing both sides by t

16t^2/t = 44t/t

16t = 44

t = 44/16

t = 2.75

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