I agree because they are right I don't really care for points btw

If a>b, c<b, and d>a, then which of the following is the correct relationship?

tatuchka [14]

x > y is the same like y < x

If a > b and b > c then a > b > c

If d > a then d > a > b > c

<h3>Answer: (D) c < b < a < d</h3>

7 0

3 years ago

What is the reciprocal of 1 and 2/3?

mr_godi [17]

Answer: 3/5

Step-by-step explanation: To find the reciprocal of 1 and 2/3, we first need to convert 1 and 2/3 to an improper fraction.

To write a mixed number as an improper fraction, first multiply the denominator times the whole number, then add the numerator.

So here, we multiply the denominator, 3, times the whole number, 1, then we add the numerator. So we have (3 x 1) + 2 or 3 + 2 which is 5.

Now we put our new number over our old denominator and we get 5/3.

However, we're not done yet. We still need to find the reciprocal.

The reciprocal describes a fraction so when we're asked to find the reciprocal of 5/3, we want to switch the numerator and denominator.

So if we switch 5/3, we get the proper fraction 3/5.

Therefore, the mixed number 1 and 2/3 is equivalent to the improper fraction 5/3, and if we switch the top and bottom numbers, we get 3/5.

7 0

3 years ago

grace scored 17 ot of 20 on her reading quiz and 20 out of 25 on her science quiz. on which quiz did grace score a higher percen

almond37 [142]

Her reading quiz, because in order to find a percent dive 17 by 20 (or 20 by 25) and multiply the answer by 100.

8 0

3 years ago

Read 2 more answers

DOES SOMEONE KNOW HOW TO DO THIS??????????????????????????????????????????????????????????????????//

lorasvet [3.4K]

To find initial price make t=0
Initial price: 1200
It represents growth because 1.025>1
It changes by 1.025*100=102.5% a year.

5 0

3 years ago

25. Tiffany deposited two checks into her account this month. One check was for $70 and the second was for $25. Her balance at t

Anna35 [415]

The first thing to do is to start with something not quite so

complicated, so you can get used to the ideas first. But let's go

ahead with this one, to check your work.

Here's one way I write these to demonstrate how to think it through:

(18/2){[(9 x 9 - 1)/ 2]-[5 x 20 - (7 x 9 - 2)]}

\____/ \_________/ \_________/

9 {[ 80 / 2]-[5 x 20 - 61 ]}

\______________/ \____________________/

9 { 40 - 39 }

\_______________________________________/

9 * 1

\____________________/

9

So you're correct, and your work was fine. The only thing I did

differently was to evaluate 18/2 earlier, because nothing stood in its

way; I could have waited as you did.

What parentheses do is to contain a subexpression that has to be fully

evaluated before it can be used in any containing expression. That's

why you work from the inside out: you can't use what's inside until

you evaluate it all, so you might as well start there. But if you

forgot to, you'd still have a reminder. Here's an example:

2[(3 + 7)(3 - 2) - 3(2 + 2)]

If I didn't bother with the inside-out "rule", I might just start

trying to evaluate at the left (paying attention to the order of

operations, of course): 2 times ... what? Well, the second number in

that multiplication is the whole thing inside [...], so I have to put

it on hold until I do that. So I focus on

(3 + 7)(3 - 2) - 3(2 + 2)

Now I start that. The first piece is (3 + 7), so I evaluate that

whole thing and get 10. Now I have to multiply it by (3 - 2), so I

stop and evaluate that, which gives 1. Now I can multiply 10 by 1 and

get 10. So I keep going; I have to subtract something from that, but

since the next bit is a product, I have to do that first. I'll have 3

times the next parenthesis; that's 3 times 4, so I have 12. The

subtraction I put off is 10 - 12 = -2.

Now, this is what the whole [...] is, so I go back and do that last

multiplication:

2*(-2) = -4

7 0

3 years ago