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marusya05 [52]
3 years ago
8

Please help me on this.

Mathematics
1 answer:
JulijaS [17]3 years ago
7 0

It would be 96 ft

Cos 30*2=60 and 6 yards=18ft and 18*2 is 36 so 36+60=96

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Destiny just received two separate gifts from her great-great-grandmother.
qaws [65]

Answer:

6 bags

Step-by-step explanation:

The first gift is a box of 18 chocolate candy bars, and the second gift is a pack of 12 cookies. Destiny wants to use all of the chocolate candy bars and cookies to make identical snack bags for her cousins. What is the greatest number of snack bags that Destiny can make? Answer: 6 bags

8 0
3 years ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions
forsale [732]

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23  = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

y = 69-19

y = 50

If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

8 0
3 years ago
PLZ HELP ILL MARK U BRAINLIEST!!
pychu [463]

Answer:

Step-by-step explanation:

The two horizontal line segments are the parallel sides of the trapezoid.

∠1 and ∠2 are corresponding angles of a transversal across parallel lines, so

∠1 is congruent with ∠2

5 0
3 years ago
James states that quadrilateral
mr_godi [17]

Using the distance formula,

AD=\sqrt{(-1-3)^{2}+(-3-(-4))^{2}}=\sqrt{17}\\\\BC=\sqrt{(5-9)^{2}+(1-0)^{2}}=\sqrt{17} \\\\\therefore \overline{AD} \cong \overline{BC}

AB=\sqrt{(-1-5)^{2}+(-3-1)^{2}}=\sqrt{52}=2\sqrt{13}\\\\CD=\sqrt{(9-3)^{2}+(0-(-4))^{2}}=\sqrt{52}=2\sqrt{13}\\\\\therefore \overline{AB} \cong \overline{CD}

Since ABCD has two pairs of opposite congruent sides, it is a parallelogram.

3 0
2 years ago
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