Answer:
The correct answer is A.

Step-by-step explanation:
Method 1
You just have to plot each point on the graph.
The one that falls within the solution region is the correct choice.
From the graph,
falls within the solution region.
See graph
Method 2
If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.
The first inequality is

If we substitute
, we get;


This statement is true.
The second inequality is

If we substitute
, we get;

This gives,

This statement is also true.
Answer: 
Step-by-step explanation:
You have the equation
.
Then, to solve for the variable
from the equation you need:
Make the subtraction of the right side of the equation:
(As the denominators are 1 and
, the least common denominator is
)

Multiply
to both sides:

Add
to both sides:

And finally divide both sides by
:

Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
5/4 is the constant of proportionality
Answer:
you got this kiddo
Step-by-step explanation: