Solution :
Mean time for an automobile to run a 5000 mile check and service = 1.4 hours
Standard deviation = 0.7 hours
Maximum average service time = 1.6 hours for one automobile
The z - score for 1.6 hours = 
= 2.02
Now checking a normal curve table the percentage of z score over 2.02 is 0.0217
Therefore the overtime that will have to be worked on only 0.217 or 2.017% of all days.
Answer:
204/325
Step-by-step explanation:
You can work this a couple of ways. We expect you are probably expected to use trig identities.
cos(A) = √(1 -sin²(A)) = 24/25
sin(B) = √(1 -cos²(B)) = 12/13
cos(A -B) = cos(A)cos(B) +sin(A)sin(B) = (24/25)(5/13) +(7/25)(12/13)
= (24·5 +7·12)/325
cos(A -B) = 204/325
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The other way to work this is using inverse trig functions. It is necessary to carry the full calculator precision if you want an exact answer.
cos(A -B) = cos(arcsin(7/25) -arccos(5/13)) = cos(16.2602° -67.3801°)
= cos(-51.1199°) ≈ 0.62769230 . . . . (last 6 digits repeating)
The denominators of 25 and 13 suggest that the desired fraction will have a denominator of 25·13 = 325, so we can multiply this value by 325 to see what we get.
325·cos(A-B) = 204
so, the exact value is ...
cos(A -B) = 204/325
I believe it’s the last answer. Rotation of 180 degrees clockwise with a dilation of 5.
I think the correct answer is :D
Answer:
multiplucation problem
Step-by-step explanation:.
