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jek_recluse [69]

3 years ago

12

an insurance company crashed 4 cars at 5 mph the cost for each 4 crashes was $417, $454, $415, $232. compute the range, sample v

ariance, and sample standard deviation cost of repair

2 answers:

Ket [755]3 years ago

7 0

Answer:

Step-by-step explanation:

i dont know

dexar [7]3 years ago

3 0

379.5? Add all together divide by 4

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2c+17.6 =6 SOLVE --------------- 4 give your answer as a decimal get brainly

scZoUnD [109]

Answer:

$\huge\boxed{x = -5.8}$

Step-by-step explanation:

2x + 17.6 = 6

Subtracting both sides by 17.6

2x = 6 - 17.6

2x = -11.6

Dividing both sides by 2

x = -11.6 / 2

x = -5.8

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3 years ago

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iVinArrow [24]

I pretty sure it’s B

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3 years ago

Consider the expression. (StartFraction 2 m Superscript negative 1 baseline n Superscript 5 Baseline Over 3 m Superscript 0 Base

suter [353]

Answer:

The correct option is option (3) 4 ÷ 25.

Step-by-step explanation:

The expression in terms of <em>m</em> and <em>n</em> is:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

Exponent rule of division:

$a^{x}\div a^{y}=a^{x-y}$

Compute the value of the expression for <em>m</em> = -5 and <em>n</em> = 3 as follows:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

$F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}$

$=\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}$

Thus, the correct option is option (3) 4 ÷ 25.

8 0

3 years ago

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What i do wrong<br> ?????

ruslelena [56]

Try to just put 10 or =10

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2 years ago

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aleksandrvk [35]

She will buy a new car.

Given p—>q and p, this means that q is true. This is because if p is true then q has to be true too. A statement when true implies false is false.

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3 years ago