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2 years ago

8

Select the favorable outcomes for rolling doubles.

1 answer:

grigory [225]2 years ago

7 0

First one sorry if it wrong

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Six out of the 12 members of the school choir are boys. In simplest form, what fraction of the choir is boys?

zubka84 [21]

Answer:

1/2

Step-by-step explanation:

3 0

2 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

8 0

3 years ago

Two families went to the event. The first family bought two children's tickets and one adult ticket and paid a total of 8.2 euro

blagie [28]

Answer:

Step-by-step explanation:

step a system of two equations c = child ticket a = adult ticket

eq 1) 2c + 1a = 8.2 multiply by 2

eq 2) 3c + 2a = 14.1

I will multiply eq 1 times TWO and subtract eq 2 from eq 1a)

eq 1a) 4c + 2a = 16.4

eq 2) 3c + 2a = 14.1

subtract (4c - 3c) + (2a -2a) = 16.4 - 14.1

c + 0 = 2.3 euros for one child ticket

Now find the adult ticket price, plug 2.3 for c into eq 1)

eq 1) 2c + 1a = 8.2

eq 1) 2(2.3) + 1a = 8.2 solve for a

4.6 + a = 8.2 substract 4.6 from both sides

a = 8.2 - 4.6

= 3.6 euros for one adult ticket

double check using eq 2) we know c and a values

eq 2) 3c + 2a = 14.1

eq 2) 3(2.3) + 2(3.6) = 14.1

6.9 + 7.2 = 14.1

14.1 = 14.1

5 0

3 years ago

The equation for picture D is 13 4/5 = w + 3 4/5. What is the solution? Write the number answer only. Please do not write the va

aksik [14]

Answer:

13 4/5 = 10 + 3 4/5

Step-by-step explanation:

4 0

2 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

3 years ago

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