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3 years ago

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A group of friends is buying popcorn and soda at the movies. They want to buy at least 4 items, and can spend up to $20.00. Popc

orn costs $3.00 each and soda costs $1.00 each. Let x represent the number of popcorns purchased, and y the number of sodas. Which system of inequalities represent this situation

2 answers:

Sloan [31]3 years ago

8 0

Answer:

x + y ≥ 4

3x + y ≤ 20

Step-by-step explanation:

Since 'x' represents the number of popcorns and 'y' represents the number of sodas, the amount they want to purchase is at least 4 items. So, the sum of these two must be greater than or equal to 4:

x + y ≥ 4

Given that they only have $20.00 to spend and the cost of popcorn is $3 and a soda costs $1, the sum can be at most $20:

3x + y ≤ 20

babymother [125]3 years ago

7 0

Answer:

x3 + y1 = 20

Step-by-step explanation:

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Ainat [17]

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3 years ago

PLS HELP WILL MARK BRAINLIST IF ANSWER IS CORRECT !! :) FILL IN THE BLANKS

andrew-mc [135]

Answer:

Part 1) The volume of the storage body is 576 cubic feet

Part 2) To find out how many boxes can she fit in the storage body, divide the volume of the storage body by the volume of each box

Part 3) Sheila can fit 64 boxes into the truck

Step-by-step explanation:

step 1

Find the volume of the storage body

we know that

The volume of the of the storage body is equal to the volume of two rectangular prism

The volume of a rectangular prism is equal to

$V=LWH$

First rectangular prism (top)

$V=(15)(6)(8-6)=180\ ft^3$

Second rectangular prism (bottom)

$V=(15-4)(6)(6)=396\ ft^3$

The volume of the storage body is

$V=180+396=576\ ft^3$

step 2

we know that

To find out how many boxes can she fit in the storage body, divide the volume of the storage body by the volume of each box

step 3

substitute the given values

$\frac{576}{9}= 64\ boxes$

therefore

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7 0

3 years ago

Solve the system by elimination. − 2 x + 2 y + 3 z = 0 − 2 x − y + z = − 3 2 x + 3 y + 3 z = 5

taurus [48]

Answer:

$x=1, y=1, z=0$

Step-by-step explanation:

we have

$-2x+2y+3z=0$ ----> equation A

$-2x-y+z=-3$ -----> equation B

$2x+3y+3z=5$ ----> equation C

adds equation A and equation C

$-2x+2y+3z=0\\2x+3y+3z=5\\-------\\2y+3y+3z+3z=0+5$

$5y+6z=5$ -----> equation D

adds equation B and equation C

$-2x-y+z=-3\\2x+3y+3z=5\\--------\\-y+3y+z+3z=-3+5$

$2y+4z=2$ -----> equation E

we have the system

$5y+6z=5$ -----> equation D

$2y+4z=2$ -----> equation E

Multiply equation E by -1.5 both sides

$-1.5(2y+4z)=-1.5(2)$

$-3y-6z=-3$ -----> equation F

adds equation D and equation F

$5y+6z=5\\-3y-6z=-3\\---------\\5y-3y=5-3\\2y=2\\y=1$

<em>Find the value of z</em>

substitute the value of y in equation E (or substitute in equation D)

$2(1)+4z=2$

$2+4z=2$

$4z=0$

$z=0$

<em>Find the value of x</em>

substitute the value of y and z in equation A (or equation B or C)

$-2x+2(1)+3(0)=0$

$-2x+2=0$

$-2x=-2$

$x=1$

therefore

The solution of the system of equations is

$x=1, y=1, z=0$

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4 years ago

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tatyana61 [14]

Answer:

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Step-by-step explanation:

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