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OLga [1]
3 years ago
9

Part A- Katelyn and Travis go on a trip. When they start out, their odometer reads 34,118 miles. If they drive 320 miles the fir

st day, what will the reading on their odometer be? Answer-34,438
Part B- Katelyn and Travis forgot to write down the mileage on the second day, but after the third day their odometer read 34,963 miles what was the average number of miles they drove during the second and third day? Answer 525 miles

I’m confused on part c. I need help figuring out how to do it!

Part C- At the end of the third day, Katelynn and Travis reached their destination. They spent 4 days at their destination and then they drove home. If it only took then 2 days to drive home, what was their average number of miles driven each day, assuming they followed the same route home with no side trips?

Please show work so I understand! I’m not about just wanting answers, but wanting to know how you got the answer you did.
Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Part B- Katelyn and Travis forgot to write down the mileage on the second day, but after the third day their odometer read 34,963 miles what was the average number of miles they drove during the second and third day? Answer 525 miles

I’m confused on part c. I need help figuring out how to do it!

Part C- At the end of the third day, Katelynn and Travis reached their destination. They spent 4 days at their destination and then they drove home. If it only took then 2 days to drive home, what was their average number of miles driven each day, assuming they followed the same route home with no side trips?

Please show work so I understand! I’m not about just wanting answers, but wanting to know how you got the answer you did.

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Solve the following system of equations.<br> -7x +4y = 10<br> -5x +3y = 8<br><br> x=<br> y=
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Answer:x=2

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Step-by-step explanation:

-7*x+4*y=10

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-5*x+3*y=8

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-2*x+y=2

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-7*2+4*y=10

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A student is setting up a relay race around the perimeter of a
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Determine which on the following logarithms is condensed correctly<br> See picture for options?
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3 years ago
What are the magnitude and direction of u+v+w ?
nevsk [136]

The magnitude and the direction of the resultant are approximately 57.871 and 198.676°.

<h3>How to determine the magnitude and the direction of a resultant</h3>

Vectors are elements with two given characteristics: Magnitude and direction. A resultant is derived from the sum of vectors, the magnitude is the norm of a vector and the direction is the orientation of a vector. The resultant and its characteristics are described below:

<h3>Resultant</h3>

\vec r = \left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)     (1)

<h3>Magnitude</h3>

\|\vec r\| = \sqrt{\left(\sum\limits_{i=1}^{n} x_{i}\right)^{2}+\left(\sum\limits_{i=1}^{n} y_{i}\right)^{2}}   (2)

<h3>Direction</h3>

\theta = \tan^{-1}\frac{\sum\limits_{i=1}^{n}y_{i}}{\sum\limits_{i=1}^{n}x_{i}}   (3)

Where \theta is resultant angle, measured in degrees.

If we know that \|\vec u\| = 90, \theta_{u} = 40^{\circ}, \|\vec v\| = 60, \theta_{v} = 20^{\circ}, \|\vec w\| = 40 and \theta_{w} = 30^{\circ}, then the resultant, its magnitude and its direction:

<h3>Resultant</h3>

\vec r = (-90\cdot \cos 40^{\circ}-60\cdot \sin 20^{\circ}+40\cdot \cos 30^{\circ}, 40\cdot \sin 30^{\circ}+60\cdot \cos 20^{\circ}-90\cdot \sin 40^{\circ})

\vec r = (-54.824, 18.531)

<h3>Magnitude</h3>

\|\vec r\| = \sqrt{(-54.824)^{2}+18.531^{2}}

\|\vec r\| \approx 57.871

<h3>Direction</h3>

\theta = \tan^{-1} \left(\frac{18.531}{-54.824}\right)

\theta \approx 198.676^{\circ}

The magnitude and the direction of the resultant are approximately 57.871 and 198.676°. \blacksquare

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/13322477

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2 years ago
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