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OLga [1]
3 years ago
9

Part A- Katelyn and Travis go on a trip. When they start out, their odometer reads 34,118 miles. If they drive 320 miles the fir

st day, what will the reading on their odometer be? Answer-34,438
Part B- Katelyn and Travis forgot to write down the mileage on the second day, but after the third day their odometer read 34,963 miles what was the average number of miles they drove during the second and third day? Answer 525 miles

I’m confused on part c. I need help figuring out how to do it!

Part C- At the end of the third day, Katelynn and Travis reached their destination. They spent 4 days at their destination and then they drove home. If it only took then 2 days to drive home, what was their average number of miles driven each day, assuming they followed the same route home with no side trips?

Please show work so I understand! I’m not about just wanting answers, but wanting to know how you got the answer you did.
Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Part B- Katelyn and Travis forgot to write down the mileage on the second day, but after the third day their odometer read 34,963 miles what was the average number of miles they drove during the second and third day? Answer 525 miles

I’m confused on part c. I need help figuring out how to do it!

Part C- At the end of the third day, Katelynn and Travis reached their destination. They spent 4 days at their destination and then they drove home. If it only took then 2 days to drive home, what was their average number of miles driven each day, assuming they followed the same route home with no side trips?

Please show work so I understand! I’m not about just wanting answers, but wanting to know how you got the answer you did.

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Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

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What is the linear function equation that best fits the data set?
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A

Step-by-step explanation:

An educated guess because I really forgot how to do these

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Step-by-step explanation:

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Simplify 3/5 x 1/4: fractions work
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Answer:

\frac{3}{20}

Step-by-step explanation:

\frac{3}{5}  \times  \frac{1}{4}

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