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OLga [1]
4 years ago
9

Part A- Katelyn and Travis go on a trip. When they start out, their odometer reads 34,118 miles. If they drive 320 miles the fir

st day, what will the reading on their odometer be? Answer-34,438
Part B- Katelyn and Travis forgot to write down the mileage on the second day, but after the third day their odometer read 34,963 miles what was the average number of miles they drove during the second and third day? Answer 525 miles

I’m confused on part c. I need help figuring out how to do it!

Part C- At the end of the third day, Katelynn and Travis reached their destination. They spent 4 days at their destination and then they drove home. If it only took then 2 days to drive home, what was their average number of miles driven each day, assuming they followed the same route home with no side trips?

Please show work so I understand! I’m not about just wanting answers, but wanting to know how you got the answer you did.
Mathematics
1 answer:
tia_tia [17]4 years ago
7 0

Part B- Katelyn and Travis forgot to write down the mileage on the second day, but after the third day their odometer read 34,963 miles what was the average number of miles they drove during the second and third day? Answer 525 miles

I’m confused on part c. I need help figuring out how to do it!

Part C- At the end of the third day, Katelynn and Travis reached their destination. They spent 4 days at their destination and then they drove home. If it only took then 2 days to drive home, what was their average number of miles driven each day, assuming they followed the same route home with no side trips?

Please show work so I understand! I’m not about just wanting answers, but wanting to know how you got the answer you did.

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nadezda [96]

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3 years ago
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Each side of a square is increasing at a rate of 5 cm/s. At what rate is the area of the square increasing when the area of the
icang [17]

Answer:

<h2>70cm/s</h2>

Step-by-step explanation:

Area of a square with side of length L is expressed as A = L². The rate at which the area is increasing will be expressed as dA/dt.

dA/dt = dA/dL * dL/dt where

dL/dt is the rate at which each side of the square is increasing.

Since dA/dL = 2L, dA/dt = 2L dL/dt

Given dL/dt = 5cm/s and the Area of the square = 49 cm²

49 = L²

L = √49

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The rate at which the area of the square is increasing is 70cm/s

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3 years ago
4[5(x + 3) - 2] + 3(x - 1)
Inessa [10]

Answer:

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