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harkovskaia [24]
3 years ago
10

The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.

Mathematics
1 answer:
Scrat [10]3 years ago
5 0

Just did a specific one of these; let's do the general case.


The point nearest the origin is (a,b).


The line from the origin through the point is


bx - ay = 0


The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):


ax + by = a^2 + b^2


ax + by -( a^2 + b^2) = 0


That's standard form; let's plug in the numbers:


4 x - 4 y - 32 = 0


x - y - 8 = 0



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Given:

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We have,

x^2+200x=166400

It can be written as:

x^2+200x-166400=0

Splitting the middle term, we get

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

(11+5i)(11-5i)

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