Answer:
I think the top and the two in the middle but I can't really see it's a blurry picture
Answer:
Step-by-step explanation:
we know that
The area of the right triangle ABC is equal to
![A=\frac{1}{2}(AB)(BC)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%28AB%29%28BC%29)
we have
![A=17\ cm^2](https://tex.z-dn.net/?f=A%3D17%5C%20cm%5E2)
![AB=(3x-2)\ cm](https://tex.z-dn.net/?f=AB%3D%283x-2%29%5C%20cm)
![BC=(x+3)\ cm](https://tex.z-dn.net/?f=BC%3D%28x%2B3%29%5C%20cm)
substitute the values
![17=\frac{1}{2}(3x-2)(x+3)](https://tex.z-dn.net/?f=17%3D%5Cfrac%7B1%7D%7B2%7D%283x-2%29%28x%2B3%29)
![34=(3x-2)(x+3)](https://tex.z-dn.net/?f=34%3D%283x-2%29%28x%2B3%29)
![34=3x^2+9x-2x-6](https://tex.z-dn.net/?f=34%3D3x%5E2%2B9x-2x-6)
![3x^2+7x-6-34=0](https://tex.z-dn.net/?f=3x%5E2%2B7x-6-34%3D0)
![3x^2+7x-40=0](https://tex.z-dn.net/?f=3x%5E2%2B7x-40%3D0)
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
![3x^2+7x-40=0](https://tex.z-dn.net/?f=3x%5E2%2B7x-40%3D0)
so
substitute in the formula
therefore
The solution is
<span>Not all functions will have intercepts</span>
Answer:
5.7686613e+16
Step-by-step explanation:
Use PEMDAS, or the orders of operations, to solve this question.
Given:
Rectangular room is 10 feet; and
1 x 1 ft tiles
The expression for this problem would be:
If we know that the width is w, while the length is w + 10,
therefore the perimeter is 2w + 2 (w + 10), so you need 4w + 20 - 4, or 4w + 16
tiles. Since you do not want to count the corners, twice.