Anyone know this ? picture shown please help
1 answer:
They're just after some straightforward algebra starting from the Law of Cosine. We don't have to evaluate any trig functions or anything like that.
We move the c² and the cosine term to their other sides,
That's it for the algebra.
a,b and c are the side lengths opposite A,B and C respectively. So a=4, b=5, c=2.
We substitute:
Answer: A. 37
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Answer:
The distance, in feet, between the strip = 12 feet.
Step-by-step explanation:
From the figure attached in relation with the question, we can deduce that crosswalk is a parallelogram where
CD/AB = CE/AE
CD = 40
CE = 50
AE = 15
Let AB = x
50x = 15 × 40
X = 12
The distance, in feet, between the strip is therefore 12 feet
Given:
Width of a garden = 10 feet
Length of the garden = 14 feet
Area of the garden and the walkway together = 396 square feet.
To find:
The width of the walkway.
Solution:
A cement walkway is added around the outside of the garden.
Let x be the width of the walkway.
The width of the garden with walkway = 10+2x
The length of the garden with walkway = 14+2x
Area of a rectangle is
Area of garden and the walkway together is
Divide both sides by 4.
Splitting the middle term, we get
Using zero product property, we get
Width of walkway cannot be negative. So, x=4.
Therefore, the width of the walkways is 4 feet.