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elena-s [515]
2 years ago
15

The volume V of a gas varies inversely as the pressure P and directly as the temperature A certain gas has a volume of 10 liters

(L), a temperature of 300 kelvins (K), and a pressure of 1.5 atmospheres (atm). If a gas has a temperature of 400 kelvins and a pressure of 5 atmospheres; what is its volume?
Mathematics
1 answer:
Ad libitum [116K]2 years ago
5 0

Answer:

Joint variation states that:

If z is directly proportional to x and inversely proportional to y,

i.e, z \propto x , z \propto \frac{1}{y}

then the equation is in the form: z = k\frac{x}{y} where k is the constant of variation.

From the given information: The volume V of a gas varies inversely as the pressure P and directly as the temperature

i.,e V \propto T , V \propto \frac{1}{P}

by definition of joint variation:

V = k\frac{T}{P}  .....[1] where k is the constant of variation.

It is also given that a certain gas has a volume of 10 liters(L) , a temperature of 300 kelvins(K), and a pressure of 1.5 atmosphere(atm).

Substitute these given values in [1] to solve for k;

10 = k\frac{300}{1.5}

Simplify:

10 = 200k

Divide by 200 both sides we have;

k = \frac{10}{200} =\frac{1}{20}

Now, if a gas has a temperature of 400 kelvins and a pressure of 5 atm.

To find the volume (V);

Now substitute the given data and value of k in [1] we have;

V = \frac{1}{20} \cdot \frac{400}{5} = \frac{20}{5} = 4

Therefore, the Volume of a gas is, 4 liters


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Answer:

Figure 3: 28.5 units²

Figure 4: 33 units²

Figure 5: 25 units²

Figure 6: 30 units²

Figure 7: 25 units²

Figure 8: 32 units²

Reasons:

Figure 3 consists of<u> </u><u>2</u> shapes, A <u>rectangle </u>and a <u>square</u>

                  ████████                                           ◣

rectangle: ████████            triangle:               █◣

                   ████████                                          ██◣

rectangle:

to calculate a <em><u>rectangle's </u></em>area: multiply the lengths of the width and height:

████████= width  8           █

                                                █    =height 3

                                                █

area=w(h)

now substitute the values of W and H:

8(3)=24

<u>rectangle area = </u><u>24</u>

Triangle:

to find the area of a <u><em>triangle</em></u>, multiply the width and height and divide by two:

◣ + ◣ = █         0.5 + 0.5 = 1

                                                █    

███=width   3                         █ =height  3

                                                █    

               

area=\frac{w(h)}{2}

now substitute W and H

area=\frac{3(3)}{2}

area\frac{9}{2}

<u>Triangle area:</u><u> 4.5</u>

Now add the Rectangle Area To the triangle Area:

4.5 + 24 = 28.5

Final answer:

AREA =2 8.5

hope this helps!

5 0
2 years ago
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