Answer:
Joint variation states that:
If z is directly proportional to x and inversely proportional to y,
i.e,
, ![z \propto \frac{1}{y}](https://tex.z-dn.net/?f=z%20%5Cpropto%20%5Cfrac%7B1%7D%7By%7D)
then the equation is in the form:
where k is the constant of variation.
From the given information: The volume V of a gas varies inversely as the pressure P and directly as the temperature
i.,e
, ![V \propto \frac{1}{P}](https://tex.z-dn.net/?f=V%20%5Cpropto%20%5Cfrac%7B1%7D%7BP%7D)
by definition of joint variation:
.....[1] where k is the constant of variation.
It is also given that a certain gas has a volume of 10 liters(L) , a temperature of 300 kelvins(K), and a pressure of 1.5 atmosphere(atm).
Substitute these given values in [1] to solve for k;
![10 = k\frac{300}{1.5}](https://tex.z-dn.net/?f=10%20%3D%20k%5Cfrac%7B300%7D%7B1.5%7D)
Simplify:
![10 = 200k](https://tex.z-dn.net/?f=10%20%3D%20200k)
Divide by 200 both sides we have;
![k = \frac{10}{200} =\frac{1}{20}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B10%7D%7B200%7D%20%3D%5Cfrac%7B1%7D%7B20%7D)
Now, if a gas has a temperature of 400 kelvins and a pressure of 5 atm.
To find the volume (V);
Now substitute the given data and value of k in [1] we have;
![V = \frac{1}{20} \cdot \frac{400}{5} = \frac{20}{5} = 4](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B20%7D%20%5Ccdot%20%5Cfrac%7B400%7D%7B5%7D%20%3D%20%5Cfrac%7B20%7D%7B5%7D%20%3D%204)
Therefore, the Volume of a gas is, 4 liters