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Marysya12 [62]
3 years ago
7

what is the equation of a line passing through (2,1) and is perpendicular to the line containing points (2,-2) and (4,10)?

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

y = -1/6x - 14

Step-by-step explanation:

The equation for the first line is y = 6x - 14

Convert the slope 6 so it becomes -1/6

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Enter the equation of the line in the form y=mx+b<br><br><br><br> pls help its due in 20 minutes!!
tia_tia [17]

Answer: y = 3x-2

Step-by-step explanation:

M = rise over run ( y2-y1 / x2-x1 )

Points I chose : ( 0,-2 ) ( 1,1 )

( 1-(-2) / 1-0 = 3/1

M = 3

Y = Mx + b

1 = (3) + b

B = -2

7 0
3 years ago
Solve the system of equations by substitution 3x+y=9z
poizon [28]

Answer:

x = 1.27

y = 5.18

Step-by-step explanation:

to solve this system of  equation by simultaneous equation we say that let

3x+y=9.............................. equation 1

-5x+2y=4 .......................... equation 2

from equation 1

3x+y=9.............................. equation 1

y = 9 -3x.............................. equation 3

substitute the value of y = 9 -3x into equation 2

-5x+2y=4 .......................... equation 2

-5x + 2( 9 -3x) = 4

-5x + 18 - 6x = 4

collect the like terms

18 - 4 = 6x + 5x

14 = 11x

divide both side by 11

14/11 = 11x/11

x = 14/11

x = 1.27

put the value of x = 1.27 into  equation 3

y = 9 -3x.............................. equation 3

y = 9 - 3( 1.27)

y = 9 - 3.82

y = 5.18

<em>to check if you are correct put the value of x and y into either equation 1 or equation 2.</em>

<em>3x+y=9.............................. equation 1</em>

<em>3( 1.27) + 5.18 = 9</em>

<em>3.81 + 5.18 = 9</em>

<em>9 = 9</em>

3 0
3 years ago
Reflect the point (2, -4) over the y-axis.
diamong [38]

Answer:

I think its a. (-2,-4)

Step-by-step explanation:

7 0
3 years ago
Which store has the better buy? Pet Smart sells 20 pounds of pet food for $13.99 or Chewy sells 50 pounds of pet food for $37.99
zimovet [89]

Answer:

pet smart sell

Step-by-step explanation:

because it is cheaper than other sell

6 0
3 years ago
If f(x)=2x^3-6x^2-16x-20f(x)=2x *3 −6x *2−16x−20 and f(5)=0, then find all of the zeros of f(x)f(x) algebraically.
mihalych1998 [28]

The zeros of the cubic function f(x) = 2x³ - 6x² - 16x - 20 are given as follows:

x = 5, x = -1 + i, x = -1 - i.

<h3>How to obtain the solutions to the equation?</h3>

The equation is defined by the rule presented as follows:

f(x) = 2x³ - 6x² - 16x - 20.

One solution for the equation is given as follows:

x = 5.

Because f(5) = 0.

Then (x - 5) is a linear factor of the function f(x), which can be written as follows:

2x³ - 6x² - 16x - 20 = (ax² + bx + c)(x - 5).

This is because the product of a linear function and a quadratic function results in a cubic function.

Now we expand the right side to begin finding the coefficients of the quadratic function that we are going to solve to find the remaining zeros:

2x³ - 6x² - 16x - 20 =  = ax³ + (b - 5a)x² + (c - 5b)x - 5c.

Then these coefficients are obtained comparing the left and the right side of the equality as follows:

  • a = 2.
  • -5c = -20 -> c = 4.
  • b = -6 + 5a = 4.

Hence the equation is:

2x² + 4x + 4.

Using a quadratic equation calculator, the remaining zeros are given as follows:

  • x = -1 + i.
  • x = -1 - i.

More can be learned about the solutions of an equation at brainly.com/question/25896797

#SPJ1

8 0
1 year ago
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