A ship sails 95 km on a bearing of 140 degrees,than further on 102km on a bearing of 260degrees,and than returns directly to its
starting point.Find the length and bearing of the return journey
1 answer:
Answer:
1. 98.7 km
2. 303.5 degree
Step-by-step explanation:
Using the alternate angle, the angle at B will be 50 + 10 = 60 degree.
To calculate the length AC of the returning journey, use cosine formula to calculate it.
To find the bearing of the returning journey, use sine rule to calculate it.
Please find the attached file for the solution
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Answer:
x = 6
Step-by-step explanation:
Given:
log₆(x) = 1
Now,
From the properties of log
logₓ (z)= (where the base of the log is equal for both numerator and the denominator)
also,
log(xⁿ) = n × log(x)
thus,
using the above properties, we can deduce the results as:
logₓ(y) = n is equivalent to y = xⁿ
therefore,
the given equation can be deduced as:
log₆(x) = 1
into,
x = 6¹
or
x = 6