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xxTIMURxx [149]
2 years ago
6

Suppose sin(A)=-0.78. use the trig identity sin^2(A)+cos^2(A)=1 and the trig identity tan(A) = sin(A)/cos(A) to find tan(A) in q

uadrant IV. round to the ten-thousandth.
a. -0.2039
b. 1.3941
c. 0.8671
d. -1.2464
Mathematics
1 answer:
Paladinen [302]2 years ago
5 0

In quadrant IV, \cos(A) is positive. So

\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = \sqrt{1-\sin^2(A)} \approx 0.6258

Then by the definition of tangent,

\tan(A) = \dfrac{\sin(A)}{\cos(A)} \approx \dfrac{-0.78}{0.6258} \approx \boxed{-1.2465}

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3 years ago
write the equation of a line that is perpendicular to the line y=-3/7-15 and that passes through the point (9,2)
SashulF [63]

Answer:

Step-by-step explanation:

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subtract the whole number from both sides

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8 0
3 years ago
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Let;

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7 0
1 year ago
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jok3333 [9.3K]

Answer:

89

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89

8 0
3 years ago
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Answer:

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