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user100 [1]
4 years ago
14

Your friend asked you to bring a couple of bags of chips to his party. there are several brands of chips,each a different size a

nd price. Write a formula that will help you find the price per gram for each bag
x= price of bag of chips
y= number of grams
z=price per gram
Mathematics
1 answer:
Lera25 [3.4K]4 years ago
6 0
Your friend asked you to bring a couple of bags of chips to his party. there are several brands of chips, each a different size and price. Write a formula that will help you find the price per gram for each bag.

x= price of bag of chips

y= number of grams

z=price per gram

z= \frac{x}{y}

Hope this helps!
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Two brothers each purchase a new pair of hiking boots and two canteens. The hiking boots cost 34.00 each. The total of their pur
polet [3.4K]

Answer:

The cost of one canteen is $7.5

Step-by-step explanation:

We are given the following in the question:

Each brother purchase a new par of boots and two canteens.

Cost of one hiking boots = $34.00

Total cost of hiking boots =

=34\times 2\\=\$68.00

Let x dollars be the cost of one canteen.

Number of canteens bought by both brother = 4

Total bill = $98.00

Thus, we can write the equation:

68 + 4x = 98

Solving the equation, we get,

68 + 4x = 98\\4x = 98-68\\4x = 30\\x = 7.5

Thus, the cost of one canteen is $7.5

4 0
3 years ago
I need assistance no links or I will report you
zalisa [80]
0.25 is the most likely answer
7 0
2 years ago
Read 2 more answers
What is the area of the shaded part of the figure below?
DanielleElmas [232]

Answer:

192 i think

Step-by-step explanation:

8 0
3 years ago
A pair of similar figures is given below. (Note: the figures are not drawn to scale.)
umka21 [38]

Answer:

Figure 1 is 84 m ....................

8 0
2 years ago
a survey of an urban university (population of 25,450) showed that 750 of 1,100 students sampled attended a home football game d
DiKsa [7]

The confidence interval for the proportion of students attending a football game is [0.6592, 0.7044].

Confidence interval can be calculated by below formula

Pcap - Z_{\alpha /2}\sqrt{\frac{Pcap(1 - Pcap)}{n} } < p < Pcap + Z_{\alpha /2}\sqrt{\frac{Pcap(1 - Pcap)}{n} }

where the left part is the lower interval and right side is the higher interval.

Pcap = 750/1100

Pcap = 0.6818

Again to calculate Z_{\alpha /2} , as we know that the level of confidence is 90 percent so its value will be 1.645

now putting the values on the both side we can get ,

0.6818 - 1.645 x 0.014 < p  <  0.6818 + 1.645 x 0.014

0.6818 - 0.023  < p < 0.6818 + 0.023

0.6588 < p < 0.7048

the nearest value is [0.6592, 0.7044]

Hence the confidence interval for the proportion of students attending a football game is [0.6592, 0.7044]

To know more on confidence interval, visit here

brainly.com/question/13067956

#SPJ4

5 0
1 year ago
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