Select all that apply. Choose the numbers that are factors of 112. (Hint: Use the divisibility rules to help you!) 2 3 4 6 7 8
2 answers:
You might be interested in
Answer:
Volume of the empty space in the can is 327.05
Step-by-step explanation:
Given:
Number of golf ball the can holds = 4
Diameter of the golf ball = 5 cm
To Find:
Volume of the empty space in the can = ?
Solution:
Step 1: Finding the volume of one golf ball
Ball is shape of the sphere
So lets use the volume of the sphere formula
Volume of the golf ball =
Radius = = 2.5 cm
Substituting the values
Volume of the golf ball
=
=
=
=
= 65.41
Step 2: Finding the volume of empty space of the can
volume of empty space of the can = volume of 5 golf ball
= 5 X 65.41
= 327.05
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so .
What is the probability that a line width is greater than 0.62 micrometer?
That is
So
Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that
There is a 0.82% probability that a line width is greater than 0.62 micrometer.