Answer:
Acute scalene triangle.
Step-by-step explanation:
Acute scalene triangle.
Sides: a = 4 b = 7 c = 8
Area: T = 13.998
Perimeter: p = 19
Semiperimeter: s = 9.5
Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad
Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad
Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad
Height: ha = 6.999
Height: hb = 3.999
Height: hc = 3.499
Median: ma = 7.246
Median: mb = 5.268
Median: mc = 4.062
Inradius: r = 1.473
Circumradius: R = 4.001
Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]
Centroid: CG[3.313; 1.166]
Coordinates of the circumscribed circle: U[4; 0.071]
Coordinates of the inscribed circle: I[2.5; 1.473]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 150.005° = 150°19″ = 0.524 rad
∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad
∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad
Answer:
6. = A.
5. = B.
4. = C.
Step-by-step explanation:
Divide 7 by 12
which would give you 0.58
so that’s 58%
Answer:
6, 2, 2/3, 2/9, 2/27, 2/81
Step-by-step explanation:
The nth term of a geometric progression is expressed as;
Tn = ar^n-1
a is the first term
n is the number of terms
r is the common ratio
Given
a = 6
r = 1/3
when n = 1
T1 = 6(1/3)^1-1
T1 = 6(1/3)^0
T1 = 6
when n = 2
T2= 6(1/3)^2-1
T2= 6(1/3)^1
T2 = 2
when n = 3
T3 = 6(1/3)^3-1
T3= 6(1/3)^2
T3= 6 * 1/9
T3 = 2/3
when n = 4
T4 = 6(1/3)^4-1
T4= 6(1/3)^3
T4= 6 * 1/27
T4 = 2/9
when n = 5
T5 = 6(1/3)^5-1
T5= 6(1/3)^4
T5= 6 * 1/81
T5 = 2/27
when n = 6
T6 = 6(1/3)^6-1
T6= 6(1/3)^5
T6= 6 * 1/243
T6 = 2/81
Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81
