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serg [7]
3 years ago
11

one days discharge at its mouth, 3 trillion gallons, could supply all of country A’s household for 5 months. how much water an a

verage household uses each month. assume there are 200 million households
Mathematics
1 answer:
serious [3.7K]3 years ago
5 0

let's use engineering notation for the sake of brevity.

1 trillion is 1,000,000,000,000, or just 1E12, twelve zeros.

1 million is then 1E6, six zeros.

we know the discharge for one day is 3E12 gallons, and that'd do just fine for country A for 5 months.  How many gallons in 1 month only?

\bf \begin{array}{ccll} gallons&months\\ \cline{1-2} 3E12&5\\ x&1 \end{array}\implies \cfrac{3E12}{x}=\cfrac{5}{1}\implies 3E12=5x \\\\\\ \cfrac{3E12}{5}=x\implies 6E11=x\implies 600000000000=x

if there are 200million inhabitants in A, namely 200E6 or 2E8 inhabitants, how many gallons per inhabitant from all those 6E11 gallons?

\bf \begin{array}{ccll} gallons&households\\ \cline{1-2} 6E11&2E8\\ x&1 \end{array}\implies \cfrac{6E11}{x}=\cfrac{2E8}{1}\implies 6E11=2E8x \\\\\\ \cfrac{6E11}{2E8}=x\implies \cfrac{600000000000}{200000000}=x\implies 3000=x

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luda_lava [24]

Answer:

(i) ∠ABH  = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding  ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH  = 180°  (Sum of interior angle in a polygon)

46° + <HBC  + 90 = 180°

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subtract 136 from both-side of the equation

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(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

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subtract 46° from both-side of the equation

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