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3 years ago

Add. (-x^3+26x^2-7-13)+(6x^4-x^3+8x+27) express the answer in standard form.

1 answer:

4 0

$(-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)\\\\=-x^3+26x^2-7-13+6x^4-x^3+8x+27\\\\=6x^4+(-x^3-x^3)+26x^2+8x+(27-7-13)\\\\=\boxed{6x^4-2x^3+26x^2+8x+7}$

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Daniel [21]

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Here is how I got my answer for 9:

Step 1: Simply $9/54$ to $1/6$ . Which leaves us with $1/6$ - $1/9$

Step 2: Find the least common denominator, which is 18.

Step 3: Make the denominators the same as the least common denominator. By multiplying $6*3$ and $9*2$ . Which leaves us with $3/18$ - $2/18$ .

Step 4: Subtract 3 and two, giving you your answer: $1/18$

Here is how I got my answer for 10:

Step 1: Simplify $6/12$ to $1/2$ . Which leaves us with $1/2$ - $4/9$

Step 2: Find the least common denominator, which is 18.

Step 3: Make the denominators the same as the least common denominator by multiplying $2*9$ and $9*2$ . Which leaves us with $9/18 - 8/18$ .

Step 4: Subtract 9 and 8, giving you your answer: $1/18$

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DerKrebs [107]

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sergij07 [2.7K]

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Bumek [7]

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