The equations y = 30x + 10 and y = –x2 + 150x + 10 model the daily sales of two car models, where x represents the number of day
s since the cars went on sale. On what day was the same number of each car sold?
1 answer:
Answer:
day 0, day 120
Step-by-step explanation:
You want to find the value of x that makes both y-values be the same:
y = y
30x +10 = -x^2 +150x +10
x^2-120x = 0 . . . . subtract the right side of the equation
x(x -120) = 0 . . . . . factor
Values of x that make this true are x=0 and x=120.
The same number of each car was sold on day 0 and day 120.
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Answer:
-2
Step-by-step explanation:
Since the roots are known and the function is a quadratic function, we can write down the function:
y = (x+3)(x-2/3) since when the roots are plugged in, the function gives 0.
Standard form means that the function has to be expanded:
y = (x+3)(x-2/3) =
y =
The constant term is -2.
Here I hope this helps you out
