Can someone please help me with numbers 1, a, b, c, 2, a, b, c

The year the Greek city of Helike disappeared is -1/5 times the year the US civil war ended. Let w represent the year the war en

Lostsunrise [7]

Answer:

ok so

-1/5x=w

w=1865

so -1/5x=1865

x=-9325

Hope This Helps!!!

5 0

2 years ago

Read 2 more answers

What ratio is equivalent to 1/7

Rzqust [24]

14/2 is equivalent to 7/1

3 0

2 years ago

Read 2 more answers

A typical cup of coffee contains about 100 mg of caffeine and every hour approximately 16% ofthe amount of caffeine inthe body i

Over [174]

Answer:

a) $\frac{dC}{dt} = rC$

And for this case we can rewrite the model like this:

$\frac{dC}{C} = r dt$

If we integrate both sides we got:

$ln C = rt + k$

If we use exponentials for both sides we got:

$C = e^{rt} e^k = C_o e^{rt}$

For this case $C_o = 100 mg$ and r = -0.16

So then our model would be given by:

$C(t) = 100 e^{-0.16 t}$

Where t represent the number of hours

b) $C(5) = 100 e^{-0.16*5}= 44.9329$

Step-by-step explanation:

Part a

For this case we can assume the proportional model given by:

$\frac{dC}{dt} = rC$

And for this case we can rewrite the model like this:

$\frac{dC}{C} = r dt$

If we integrate both sides we got:

$ln C = rt + k$

If we use exponentials for both sides we got:

$C = e^{rt} e^k = C_o e^{rt}$

For this case $C_o = 100 mg$ and r = -0.16

So then our model would be given by:

$C(t) = 100 e^{-0.16 t}$

Where t represent the number of hours

Part b

For this case we can replace the value t=5 into the model and we got:

$C(5) = 100 e^{-0.16*5}= 44.9329$

7 0

3 years ago

HELP!!

Step2247 [10]

That’s easy it’s 200$

8 0

2 years ago

A simple random sample with n = 58 provided a sample mean of 24.5 and a sample standard deviation of 4.4. (Round your answers to

nasty-shy [4]

Answer: (23.53, 25.47)

Step-by-step explanation:

The confidence interval for population mean(when population standard deviation is unknown) is given by :-

$\overline{x} \pm\ t^*\dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = sample mean

n = sample size.

s = sample standard deviation.

t* = Critical value.

Given : $\overline{x}=24.5$

s= 4.4

Confidence level = 90% =0.090

Significance level = $\alpha=1-0.90=0.10$

Sample size : n= 58

Degree of freedom : df= n-1= 57

Using t-distribution table , the critical value :

$t_{\alpha/2,\ df}= t_{0.05,\ 57}=1.6720$

Then, the confidence interval will be :-

$24.5 \pm\ (1.6720)\dfrac{4.4}{\sqrt{58}}$

$24.5 \pm\ (1.6720)\dfrac{4.4}{7.61577310586}$

$24.5 \pm\ 0.965995165263\approx24.5\pm0.97\\\\=(24.5-0.97,\ 24.5+0.97)\\\\=(23.53,\ 25.47)$

Hence, a 90% confidence interval for the population mean = (23.53, 25.47)

6 0

3 years ago