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Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Answer:

It looks blurry and faded

Step-by-step explanation:

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Solve the inequality -6c< -12

sweet [91]

Answer: c<2

Step-by-step explanation:

-6c<-12

c<-12/-6

c<2

7 0

3 years ago

What value of x will make parallelogram ABCD a rhombus?

Vesnalui [34]

Value of x=34degree will make parallelogram ABCD a rhombus

6 0

3 years ago

Read 2 more answers

for the school play adult tickets cost 4$ and children tickets cost 2$ natalie is working at the ticket counter and just sold 20

lilavasa [31]

Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be

4x + 2y = 20

There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.

When x=0,
4(0) + 2y = 20
y = 10

When x=1,
4(1) + 2y = 20
y = 8

When x=2,
4(2) + 2y = 20
y = 6

When x=3,
4(3) + 2y= 20
y = 4

When x = 4,
4(4) + 2y = 20
y = 2

When x = 5,
4(5) + 2y = 20
y = 0

When x = 6,
4(6) + 2y = 20
y = -2

A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:

Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0

6 0

3 years ago

How do you solve this please help

coldgirl [10]

Answer:

thanks

Step-by-step explanation:

I have been patient trying to get a job

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3 years ago

In Happyville, the ideal family has four children, at least two of which are girls. If you randomly select a Happyville family t

sleet_krkn [62]

Answer:

0.3125 = 31.25% probability that it is not ideal.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it is a girl, or they are not. The probability of a child being a girl is independent of any other child. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$