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solong [7]
3 years ago
8

Help I really need the answer to this.​

Mathematics
2 answers:
JulijaS [17]3 years ago
8 0

It’s either b or c

It either of those.

Anna35 [415]3 years ago
4 0

Answer:

3

Step-by-step explanation:

The sides are congruent so you can write the equation (4x+9)=21.

Now you subtract 9 from 21 and you get 4x=12.

All you gotta do now is divide and you get x=3.

Hope this helps!:)

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The proper way to write a single digit whole number in a sentence is:
Fynjy0 [20]
The correct answer for the given question above would be the last option. The proper way to write a single digit whole number if it is in a sentence should be SPELLED OUT and not written in numerals or roman numerals. For example, I have SIX apples; and not I have 6 apples.
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3 years ago
Asap help as fast as you can please
Arte-miy333 [17]
Dear Yakiii,

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3 years ago
Read 2 more answers
Type the correct answer in each box. Round your answers to two decimal places. Subtract vector v = <2, -3> from vector u =
expeople1 [14]

u - v = <5, 2> - <2, - 3> = <5 - 2, 2 + 3> = <3, 5>

given a vector <u, v> then the magnitude is √ (u² + v² ) and it's angle of direction is

θ = tan^{-1}(\frac{v}{u})

thus the magnitude of <3, 5> = √(3² + 5²) = √34 ≈ 5.83 ( to 2 dec. places )

Θ = tan^{-1}(\frac{5}{3}) = 59.04° ( to 2 dec. places )



3 0
3 years ago
Find the minimum value of the function f(x)=x^2+5x-6
mash [69]
<h3><u>Explanation</u></h3>
  • Method 1 (Formula)

\begin{cases}h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{2a}  \end{cases}

The vertex of Parabola is the maximum/minimum point depending on the value of a.

  • Find Vertex

<u>h-value</u>

h =  -  \frac{5}{2(1)}  \\ h =  -  \frac{5}{2}

<u>k-value</u>

k =  \frac{4(1)( - 6) -  {(5)}^{2} }{4(1)}  \\ k =  \frac{ - 24 - 25}{4}  \\ k =  \frac{ - 49}{4}  \\ k =  -  \frac{49}{4}

The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.

  • Method 2 (Derivative)

This is Calculus method. We simply differentiate the function then substitute y' = 0.

  • Differentiate Function

f'(x) = 2 {x}^{2 - 1}  +  {5x}^{1 - 1}  - 0 \\ f'(x) = 2x + 5

Substitute f'(x) = 0

0 = 2x + 5 \\  - 5 = 2x \\   -  \frac{5}{2}  = x

Substitute x = -5/2 in the original equation.

f(x) =  {( -  \frac{5}{2} )}^{2}  + 5( -   \frac{5}{2} ) - 6 \\ f(x) =  \frac{25}{4}  -  \frac{25}{2}  - 6 \\ f(x) =  \frac{25}{4}  -  \frac{50}{4}  -  \frac{24}{4}  \\ f(x) =  \frac{25}{4}  -  \frac{74}{4}  \\ f(x) = -   \frac{49}{4}

<h3><u>Answer</u><u /></h3>

<u>\sf{the  \:  \: minimum  \:  \: value \:  \:  is   \:  \: -  \frac{49}{4}  \:  \: at \:  \:  x =  -  \frac{5}{2} }</u>

4 0
3 years ago
น. <br><img src="https://tex.z-dn.net/?f=x%20%3D%201%20-%20%20%5Csqrt%7B2%7D%20find%20%20%5C%3A%28x%20-%20%20%5Cfrac%7B1%7D%7Bx%
Nastasia [14]

Answer:

Step-by-step explanation:

\frac{1}{x}=\frac{1}{1-\sqrt{2}}\\\\=\frac{1*(1+\sqrt{2})}{(1-\sqrt{2})(1+\sqrt{2})}\\\\=\frac{1+\sqrt{2}}{1^{2}-(\sqrt{2})}\\\\=\frac{1+\sqrt{2}}{1-2}\\\\=\frac{1+\sqrt{2}}{-1}\\\\= -[1+\sqrt{2}]\\\\x-\frac{1}{x}=1-\sqrt{2}-(-[1+\sqrt{2}])\\\\=1-\sqrt{2}+1+\sqrt{2}\\\\=2

8 0
3 years ago
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