Question

Factoring the expression 20a^3b^3 – 24a^5b^2 + 4a^3b^2 gives a new expression of the form

Answer 1

Answer:

$U = 4\\W = -6\\V = 5\\Z = 1\\x = 3\\y = 2$

Step-by-step explanation:

Then given expression is:

$20a^3b^3-24a^5b^2+4a^3b^2$

To express the given expression in the form:

$Ua^xb^y(Wa^2+Vb+Z)$

and to find the values of $U, W, V, Z, x, y$.

First of all, let us check the maximum common powers of $a, b$ in each term from the given expression.

The maximum common power of $a$ is 3 and

The maximum common power of $b$  is 2.

So, we can take $a^3b^2$ common out of each term.

And maximum common coefficient that can be taken out common is 4.

Taking 4$a^3b^2$ common from each term of given expression, we get:

$4a^3b^2(-6a^2+5b+1)$

Now, let us compare the given term with:

$4a^3b^2(-6a^2+5b+1)$ = $Ua^xb^y(Wa^2+Vb+Z)$

Now, the values that we get the following values:

$U = 4\\W = -6\\V = 5\\Z = 1\\x = 3\\y = 2$

which is our answer.