Consider the following system of two linear equations:

Mathematics

1 answer:

harkovskaia [24]1 year ago

4 0

Hello,

Answer:

The last graph (2;3)

Step-by-step explanation:

2x + 3y = 12

2x – 3y = 0

2x + 3y = 12

2x = 3y

3y + 3y = 12 ⇔ 6y = 12 ⇔ y = 12/6 = 2

2x + 3 × 2 = 12 ⇔ 2x + 6 = 12 ⇔ 2x = 6 ⇔ x = 6/2 = 3

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What are the coordinates of the point that is 1/6 of the way from a(14,-1) b(-4,23)

Nimfa-mama [501]

Answer:

$\text{The coordinates of point is }P(a,b)=(\frac{80}{7}, \frac{17}{7})$

Step-by-step explanation:

$\text{Given the coordinates of point that is }\frac{1}{6}\text{ of the way from a(14, -1), b(-4, 23)}$

$\text{If a point }P(a, b)\text{ divides the line joining two points }(x_1,y_1)\text{ and }(x_2, y_2)\\ \text{ in the ratio m:n internally, then the coordinates of point P are given by}$

$P(a,b)=(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n})$

The two points given are a(14, -1), b(-4, 23) and ratio m:n=1:6

$P(a,b)=(\frac{1(-4)+6(14)}{1+6}, \frac{1(23)+6(-1)}{1+6})$

$P(a,b)=(\frac{80}{7}, \frac{17}{7})$

8 0

4 years ago

Complete the equation of the line through (4,-8)(4,−8)left parenthesis, 4, comma, minu

In-s [12.5K]

Equation of a line is in the form y = mx+c, where m is the gradient and c is the y-intercept.

First step is to find the gradient.

m = (y2-y1)/(x2-x1)
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We have y = (13/4)x + c

Now we replace one of the coordinates to find c. Let’s replace (4,-8)

We have: -8 = (13/4)*4 + c

-8=13+c
c=-8-13= -21

Therefore, equation of line is:

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HELPPP IT WOULD BE APPRECIATED :)

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Step-by-step explanation:

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3 years ago

What is a/9 =-4 I really need help on this one

pashok25 [27]

The answer I believe is -36