What is the answer A B C D

Please help really I need it thank you :)

tamaranim1 [39]

Answer:

44, 6, and 24 are not perfect square

Step-by-step explanation:

Perfect square are numbers that can be square rooted with a result of a perfect whole number.

√16=4

√44= 6.63324...

√81= 9

√6= 2.44948...

√49= 7

√24= 4.898997...

6 0

2 years ago

6279÷4= could you help me with this problem

Feliz [49]

Answer: 1,569.75

Step-by-step explanation:

6279÷4=1,569.75

:)

7 0

2 years ago

a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

Step-by-step explanation:

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

The first term :

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

The common ratio (r) :

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

To find the recursive rule :

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

3 0

3 years ago

Find the value of the derivative (if it exists) at the indicated extremum. (If an answer does not exist, enter DNE.)

Liono4ka [1.6K]

Answer:

The answer is "0".

Step-by-step explanation:

Please find the correct question in the attached file.

Given value:

$\to f(x) =\frac{x^2}{x^2+5}\\\\$

Formula:

$\bold{\frac{d}{dx} \frac{u}{v} = \frac{ v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}}$

$\to f'(x) =\frac{(x^2+5) 2x -2x^3 (2x)}{(x^2+5)^2}\\\\\to f'(0) =\frac{(0^2+5)2(0) -4(0)^4}{(0^2+5)^2}\\\\\to f'(0) =\frac{(0)(5) -2(0)}{(5)^2}\\\\\to f'(0) =\frac{0 - 0}{(5)^2}\\\\\to f'(0) =\frac{0}{25}\\\\\to f'(0) = 0$

6 0

2 years ago

Given the function below, find x so that, f(x)=10

ch4aika [34]

To find the slope and the -intercept of the line, first write the function as an equation, by substituting for

y=10
y=0x+10
y=0x+10 , m=0
y=0x+10 , m=0 , b=10

m=0 , b=10

The slope of the line is m=0 and the y-intercept is b=10

7 0

2 years ago