Answer: A & B are the same answer --> 96, max
<u>Step-by-step explanation:</u>
Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:
- If m > n, then there is no H.A.
- If m = n, then y = coefficient of numerator ÷ coefficient of denominator
- If m < n, then y = 0
In the given problem, m = 1 and n = 1 so the H.A. is:

This is the maximum number of moose that the forest can sustain at one time.
2.7 would be 2 7/10. Correct?
2logx = log64
2logx = log(2)⁶
2logx = 6.log(2)
logx = 3log (2)
logx=log(2)³ ===> x = 2³ & x = 8