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tensa zangetsu [6.8K]
3 years ago
11

A piece of pipe is 303/4 inches long. If five pieces, each 41/3 inches long, are cut from the pipe, how many inches of pipe rema

in?
A. 9 3/4 inches
B. 26 3/4 inches
C. 26 5/12 inches
D. 9 1/12 inches
Mathematics
1 answer:
galina1969 [7]3 years ago
3 0
So, what is the total lenght of the pieces that wer cut off?

we multiply the lenght by the number:

4 \frac{1}{3}*5=20+\frac{5}{3}=21\frac{2}{3}

and we subtract this from the original pipe, that is

30\frac{3}{4}-21\frac{2}{3}

we need to bring the two fractions to the same denominator (by multiplying the fraction art in the first by 3 and 4 the second):

30\frac{9}{12}-21\frac{8}{12}=9 \frac{1}{12}

so the correct answer is D!




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9 to the power 3 + 3 to the power 2 + 6 to the power 3 + 15 power 2 equals to how much
Llana [10]
Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!


So-------

9^3=729

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6^3=216

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If you have any questions on this, I'm happy to help you. :)




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A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

-16x^2+64x-5=0

For simplicity, divide both sides by -1:

16x^2-64x+5=0

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

Evaluate:

\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0
3 years ago
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