What is the volume of this prism?

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

When finding the length of the hypotenuse of a right triangle why might you approximate the answer?

sammy [17]

Answer:

Because the hypotenuse might not be a perfect square

Step-by-step explanation:

8 0

3 years ago

Explain the difference between the theoretical probability and finish odds

stepladder [879]

Answer:

Theoretical probability is what that you expect to happen to you while experimental is what actually happen when you try it out.

5 0

3 years ago

Read 2 more answers

two-point charges are 10.0 cm apart and have charges of 2.0 uc and -2.0uc respectively What is the magnitude of the electrical f

maks197457 [2]

Answer:

The electric field generated by a point charge is given by:

where

is the Coulomb's constant

Q is the charge

r is the distance from the charge

We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them.

Let's calculate first the electric field generated by the positive charge at that point:

where the positive sign means its direction is away from the charge.

while the electric field generated by the negative charge is:

where the negative sign means its direction is toward the charge.

If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:

Read more on Brainly.com - brainly.com/question/9699355#readmore

Step-by-step explanation:

6 0

3 years ago

If angle c=60° , b=5 ,a=4 then find the value of the c ?

Lyrx [107]

Answer:

c=sqrt21

Step-by-step explanation:

angle c is the angle between a and b, so use the cos law

c^2=a^2+b^2-2*a*b*cosC

c^2= 16+25-2*4*5*1/2

c^2=21

c=sqrt21

5 0

3 years ago