Let the width be x.
Length = 5 + x
Perimeter = 58
2(l + w) = 58
2(5 + x + x) = 58
2(5 + 2x) = 58
10 + 4x = 58
4x = 48
x = 12
Hence, the length is 17 cm and the width is 12 cm.
The scale factor is 5
-2*5 is=-10
6*5=30
Answer:
Here, Diameter of the whole tube = 10 m
Diameter of the inner tube= 10mm - 2 mm= 8mm
Now,
Area of the shaded region =1/4 ×πd^2
=1/4×3.14×8^2
=50.24 mm^2
There should be 60 possible outcomes.
