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Savatey [412]
3 years ago
7

Which value has an absolute deviation of 5 from the mean of this data set?

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Answer: 28

Step-by-step explanation: see prev. explanation

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3 years ago
A, B, and C are points on the circumference of a circle, centre 0. AOB is a diameter of the circle. Prove that angle ACB is 90°
ki77a [65]

Answer:

Kindly refer to explanation.

Step-by-step explanation:

Given that:

A,B and C are 3 points on circumference of circle with centre O.

AOB is diameter.

Kindly refer to the attached image.

To prove:

\angle ACB = 90^\circ

Solution:

Let \angle A = x and \angle B = y.

<em>Construction</em>: Join point  A with centre O.

Considering \triangle AOC:

Side AO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, \angle ACO=\angle A=x

Considering \triangle BOC:

Side BO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, \angle BCO=\angle B=y

\angle ACB = \angle ACO + \angle BCO = x+y ...... (1)

Now, in \triangle ABC:

Using angle sum property of triangle:

\angle A + \angle B + \angle ACB =180^\circ\\\Rightarrow x+y+x+y=180^\circ\\\Rightarrow 2(x+y)=180^\circ\\\Rightarrow x+y=90^\circ

By equation (1):

\angle ACB = 90^\circ

Hence proved.

5 0
3 years ago
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