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aliya0001 [1]
3 years ago
10

Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 26, the length of A C is 10, and the leng

th of B C is 24. Given right triangle ABC, what is the value of tan(A)? Five-thirteenths Twelve-thirteenths Twelve-fifths Thirteen-twelfths
Mathematics
2 answers:
ExtremeBDS [4]3 years ago
7 0

Answer:

<h2>The right option is twelve-fifths</h2>

Step-by-step explanation:

Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.

Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;

Tan (A) = opp/adj

Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;

tan(A) = BC/AC

tan(A) = 24/10

tan(A) = 12/5

The right option is therefore twelve-fifths

Svet_ta [14]3 years ago
4 0

Answer:

12/5

Step-by-step explanation:

100% correct

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Answer:

17/9

Step-by-step explanation:

The scaled figure in the right is larger, thus the scale factor is greater than 1.

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Rachel spent $38 for dinner. This was $10 less than 3 times what she spent for a movie. How much was the movie?
MatroZZZ [7]
So, first you subtract 10 from 38 which gives three times of the money spent for the movie. Then you divide 3 from it to give you the answer.

38-10 = 28
28/3 = 9.37 dollars
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3 years ago
Each of three jars is filled with blackcurrant, raspberry, or strawberry jam. The labels on each are "raspberry", "strawberry,"
gavmur [86]

Answer:

Raspberry

Step-by-step explanation:

Strawberry label = raspberry

Raspberry label =strawberry

Strawberry and Raspberry label = blackcurrant

5 0
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4. What is the slope of a line that is parallel to the line described by 3x + 2y = 8?
VikaD [51]
The answer is :

B. M=3/2
6 0
3 years ago
Use the method of lagrange multipliers to find
Yanka [14]

Answer:

a) The function is: f(x, y) = x + y.

The constraint is: x*y = 196.

Remember that we must write the constraint as:

g(x, y) = x*y - 196 = 0

Then we have:

L(x, y, λ) = f(x, y) +  λ*g(x, y)

L(x, y,  λ) = x + y +  λ*(x*y - 196)

Now, let's compute the partial derivations, those must be zero.

dL/dx =  λ*y + 1

dL/dy =  λ*x + 1

dL/dλ = (x*y - 196)

Those must be equal to zero, then we have a system of equations:

λ*y + 1 = 0

λ*x + 1 = 0

(x*y - 196) = 0

Let's solve this, in the first equation we can isolate  λ to get:

λ = -1/y

Now we can replace this in the second equation and get;

-x/y + 1 = 0

Now let's isolate x.

x = y

Now we can replace this in the last equation, and we will get:

(x*x - 196) = 0

x^2 = 196

x = √196 = 14

then the minimum will be:

x + y = x + x = 14 + 14 = 28.

b) Now we have:

f(x) = x*y

g(x) = x + y - 196

Let's do the same as before:

L(x, y, λ) = f(x, y) +  λ*g(x, y)

L(x, y, λ) = x*y +  λ*(x + y - 196)

Now let's do the derivations:

dL/dx = y + λ

dL/dy = x + λ

dL/dλ = x + y - 196

Now we have the system of equations:

y + λ = 0

x + λ = 0

x + y - 196 = 0

To solve it, we can isolate lambda in the first equation to get:

λ = -y

Now we can replace this in the second equation:

x - y = 0

Now we can isolate x:

x = y

now we can replace that in the last equation

y + y - 196 = 0

2*y - 196 = 0

2*y = 196

y = 196/2 = 98

The maximum will be:

x*y = y*y = 98*98 = 9,604

6 0
3 years ago
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