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ki77a [65]
3 years ago
13

What step do I do first

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0
You would have to Find the GCF
Alisiya [41]3 years ago
5 0
The first step I would suggest to you is to convert the mixed numbers into improper fractions.
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The answer is t=1.

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Nathan and Steven stacked boxes on a shelf . Nathan lifted 13 boxes and Steven lifted 15 boxes . The boxes that Nathan lifted ea
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The answer is N=13(x+12), where x represents the amount of pounds Steven's boxes weighed and N represents the total number of pounds Nathan lifted. 
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The price of an item has been reduced by 25% . The original price was $20 . What is the price of the item now?
Verizon [17]

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ok for this problem lets subtract 25 for 100 to get 75 so know we know we have to multiple 20 by 0.75 to get 15 dollars for the reduced price

5 0
3 years ago
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Using the information regarding the proportion of work time linguists study a new language, choose the correct conclusion for th
Vlada [557]

Answer:

The  correct option is  B

Step-by-step explanation:

From the question we are told that

  The null hypothesis is  H_o : p = 0.10

   The alternative hypothesis is  H_a  :  p >  0.10

   The  p-value  is  p-value  =  0.09

   The  level of  significance is  \alpha = 0.025

   

From the given values p-value >  \alpha so we fail to reject the null hypothesis

So there is NOT sufficient evidence to conclude the proportion of work time linguists study a new language is more than 10%.

5 0
3 years ago
B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,
Nadusha1986 [10]

Answer:

\huge{ \fbox{ \sf{Rs \: 40000}}}

Step-by-step explanation:

\sf{Let \: CP \: ( \: cost \: price) \: be \: x}

\sf{Loss \: \% \:  = 5  \% \: }

\sf{Selling \: price = CP \:  -  \: loss \: \% \: of \: CP}

\mapsto{ \sf  x -  \frac{5}{100}  \times x}

\mapsto{ \sf{x -  \frac{x}{20} }}

\mapsto{ \sf{  \frac{x \times 20 - x}{20} }}

\mapsto{ \sf{ \frac{20x - x}{20}}}

\mapsto{ \sf{ \frac{19x}{20}}}

Now, Finding the New selling price

\sf{New \: SP \: ( \: selling \: price)} =  \frac{19x}{20}  + 5200

\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}

\mapsto{ \sf{ \frac{19x + 10400}{20}}}

Finally, finding the Cost price :

We have, Profit % = 8 %

\sf{Cost \: price = Selling \: price \:  -  \: P\% \: of \: CP}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  - 8\% \: of \: x}}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{8x}{100} }}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{2x}{25} }}

\mapsto{ \sf{x =  \frac{5(19x + 104000) - 2x \times 4}{100} }}

\mapsto{ \sf{x =  \frac{95x + 520000 - 8x}{100} }}

\mapsto{ \sf{x =  \frac{87x + 520000}{100}}}

\mapsto{ \sf{100x = 87x + 520000}} \:  \: ( \sf{Cross \: multiplication}

\mapsto{ \sf{100x - 87x = 520000}}

\mapsto{ \sf{13x = 520000}}

\mapsto{ \sf{x =  \frac{520000}{13}}}

\mapsto{ \boxed {\sf{x = 40000}}}

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

5 0
3 years ago
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