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Mrac [35]
3 years ago
6

What is 20×40+3×9÷3+4

Mathematics
2 answers:
-Dominant- [34]3 years ago
5 0
<span><span /><span>The answer to that problem is 813. When you are given a problem like this, you can answer it by using the MDAS technique. MDAS stands for multiplication, division, addition, and subtraction. Since you are following the MDAS technique, you are asked to answer the equation based on MDAS order. To put this simply, look at the example below:

     20x40+3x9/3+4
     800+3x9/3+4
     800+27/3+4
     800+9+4
     809+4
     813</span></span>  

You can clearly see the MDAS order by following the bold text.    


Zarrin [17]3 years ago
3 0
Multiplication and division must be done before addition and subtraction. Therefore:

(20×40)+(3×9÷3)+4
=800+9+4
=813
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A used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a l
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Answer:

C. 1000 loss.

Step-by-step explanation:

Let x represent purchase price of each car.

We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.

We can represent the car that dealer sold with 25% profit to find purchase price as:

x+0.25x=20,000

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\frac{1.25x}{1.25}=\frac{20,000}{1.25}

x=16,000

Therefore, the purchase price of 1st car was $16,000.

We can represent the car that dealer sold with 20% loss to find purchase price as:

x-0.20x=20,000

0.80x=20,000

\frac{0.80x}{0.80}=\frac{20,000}{0.80}

x=25,000

Therefore, the purchase price of 2nd car was $25,000.

The total purchase price of both cars would be 16,000+25,000=41,000

The total sale price of both cars 20,000+20,000=40,000.

We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.

Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.

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