The trigonometric function is given as

Apply the half angle identity to find the value of tan 75 ,

Here,

![\tan (75^{\circ})=\frac{\frac{1}{2}}{1-\frac{\sqrt[]{3}}{2}}=\frac{\frac{1}{2}}{\frac{2-\sqrt[]{3}}{2}}^{}](https://tex.z-dn.net/?f=%5Ctan%20%2875%5E%7B%5Ccirc%7D%29%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%7D%7B1-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%7D%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%7D%7B%5Cfrac%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%7D%5E%7B%7D)
![\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}](https://tex.z-dn.net/?f=%5Ctan%2075%5E%7B%5Ccirc%7D%3D%5Cfrac%7B1%7D%7B2-%5Csqrt%5B%5D%7B3%7D%7D)
Now rationalize the function.
![\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}\times\frac{2+\sqrt[]{3}}{2+\sqrt[]{3}}=\frac{2+\sqrt[]{3}}{4-3}=\frac{2+\sqrt[]{3}}{1}](https://tex.z-dn.net/?f=%5Ctan%2075%5E%7B%5Ccirc%7D%3D%5Cfrac%7B1%7D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%5Ctimes%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%3D%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B4-3%7D%3D%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B1%7D)
Again simplify the trigonometric function,

Hence the answer is 3.732.
Answer:
1379.31meters is the line-of-sight distance from the television camera to the base of the stadium .
Step-by-step explanation:
As given
A blimp provides aerial television views of a tennis game.
The television camera sights the stadium at a 17degrees angle of depression. The altitude of the blimp is 400m.
Now by using the trignometric identity .

As the figure is given below .
Perpendicular = AC = 400 m
Hypotenuse = AB

Putting all the values in the identity .



AB = 1379.31 meters
Therefore the 1379.31 meters is the line-of-sight distance from the television camera to the base of the stadium .
Step-by-step explanation:
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