Question

The polynomial function f (x) = 5 x Superscript 5 Baseline + sixteen-fifths x minus 3 is graphed below. On a coordinate plane, point P is shown on the graph of a function. Point P is at (0.6, 0). Which is a potential rational root of f(x) at point P?

Answer 1

NSWER

The root at point P may be 3/5

EXPLANATION

The given function is

$f(x)=$$5x^{5}$$+$$\frac{16}{5} x$$-3$

The potential rational roots are all factors of -3 expressed over all factors of 5.

These are:

$±\frac{1}{5} , ±\frac{3}{5}$

Since the root of f(x) at P is closer to 1 that zero and it is positive , that potential may be $\frac{3}{5}$

Answer 2

Answer:

3/5

Step-by-step explanation:

What divisor is represented by the synthetic division below? x + 5. One factor of  x^3+x^2+x+1. If f(-5) = 0, what are all the factors of the function mc022-... -4 and 3. The polynomial function f(x) = 5x5 + 3x - 3 is graphed below. The root at point P maybe 3/5  3.