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QveST [7]
2 years ago
10

dave builds a crate to hold veggies. the volume of the crate is 48 cubic feet. the base area of the crate is 16 square feet. wha

t is the height of the crate?
Mathematics
1 answer:
Aliun [14]2 years ago
3 0

16 sq ft = 2 ft x 8 ft

               4 ft x 4 ft

but..

4 ft x 4 ft x 4 ft = 64 cubic ft

So 4 cannot be the height of this crate.

h represents the height of the crate (defined variable)

2 ft x 8 ft x h = 48 cubic ft

16h = 48

h = 3 ft

The height of the crate is 3 feet.

Check:

2 ft x 8 ft x 3 ft = 48 ft ³

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Answer:

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Step-by-step explanation:

5 0
3 years ago
Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I
Elden [556K]

Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

Security\ A = 2\ mins+ \frac{20}{60}\ min

Security\ A = 2\ mins+ \frac{1}{3}\ min

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\ mins, 40\ secs

Security\ B = 1\ mins+ 40\ secs

Security\ B = 1\ mins+ \frac{40}{60}\ min

Security\ B = 1\frac{2}{3}\ min

So, we have:

Security\ A = 2\frac{1}{3}\ min

Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...

Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

Time = 11\frac{2}{3}\ min

<em>This implies that they go on round after </em>11\frac{2}{3}\ min<em></em>

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